Question

(x-5-y) hole square. simplify​

Answer 1

Correct Question:

$\tt (x-y-5)^2, simplify$

Your Answer

We know that

$\tt \blacktriangleright (a+b+c)^2 = a^2 +b^2+c^2 +2ab +2bc +2ac -----(1)\\\\ \tt Now, Comparing \ \ the \ \ terms\\\\ \tt \star a = x \\\\ \tt \star b = -5 \\\\ \tt \star c = -y \\\\ \tt Replacing \ \ values \ \ in \ \ equation (1)$

$\tt (x-5-y) \\\\ \tt = (x)^2 + (-5)^2 + (-y)^2 + 2(x)(-5) + 2(-5)(-y) + 2(x)(-y) \\\\ \tt = x^2 + 25 + y^2 - 10x + 10y - 2xy$

Other Formulas

$\tt \star (a + b)^2 = a^2 + b^2 + 2ab \\\\ \tt \star(a - b) 2 = a^2 + b^2 - 2ab \\\\ \tt \star a^2 - b^2 = (a - b) (a + b) \\\\ \tt \star (x + a) (x + b) = x^2 + (a + b) x + ab \\\\ \tt \star(a + b + c)^2 = a^2 + b^2 + c^2 + 2ab + 2bc + 2ca \\\\ \tt \star[a + (-b) + (-c)]^2 = a^2 + (-b)^2 + (-c)^2 + 2a (-b) + 2 (-b) (-c) + 2a (-c) \\\\ \tt \star (a - b - c)^2 = a^2 + b^2 + c^2 - 2ab + 2bc - 2ca.$