Math, asked by betty19, 11 months ago

x^6-1.Please help me. I will mark as brainliest.​

Answers

Answered by shameemamk
7

Answer: (x+1)(x-1)(x²+x+1)(x²-x+1)

Step-by-step explanation:

x⁶-1 = (x³)² - 1²

=(x³+1)(x³-1)

We know that (a-b)³=a³-b³-3ab(a-b)

so a³-b³=(a-b)³+3ab(a-b)

=(a-b)[(a-b)²+3ab

=(a-b)(a²+ab+b²)

Similarly (a+b)³=a³+b³+3ab(a+b)

so a³+b³=(a+b)³-3ab(a+b)

=(a+b)[(a+b)²-3ab

=(a+b)(a²-ab+b²)

∴x⁶-1 =(x³+1)(x³-1)

=(x+1)(x²-x+1)(x-1)(x²+x+1)

=(x+1)(x-1)(x²+x+1)(x²-x+1)


betty19: thanks
Answered by tejashwi402
0

Answer:

(x+1)(x-1)(x²+x+1)(x²-x+1)

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