Question

(x+6)(x-6)-(x-5)^2=40-17(x-2)​

Answer 1

Answer:

(x+6)(x-6)-(x-5)^2=40-17(x-2)

We move all terms to the left:

(x+6)(x-6)-(x-5)^2-(40-17(x-2))=0

We use the square of the difference formula

x^2-(x-5)^2-(40-17(x-2))-36=0

We calculate terms in parentheses: -(40-17(x-2)), so:

40-17(x-2)

determiningTheFunctionDomain

-17(x-2)+40

We multiply parentheses

-17x+34+40

We add all the numbers together, and all the variables

-17x+74

Back to the equation:

-(-17x+74)

We get rid of parentheses

x^2-(x-5)^2+17x-74-36=0

We add all the numbers together, and all the variables

x^2+17x-(x-5)^2-110=0

We move all terms containing x to the left, all other terms to the right

x^2+17x-(x-5)^2=110

Answer 2

here is your answer, hope it's helpful