x(6x-5y)-4(6x-5y)^2
factorise it
Answers
Answered by
40
x(6x - 5y) - 4(6x-5y)^2
(6x - 5y) is a factor, so
(6x - 5y)[x - 4(6x - 5y)]
(6x - 5y)[x - 24x + 20y]
(6x - 5y)(20y - 23x)
x(6x - 5y) - 4(6x - 5y)^2
let
z = 6x - 5y
xz - 4z^2
-4z^2 + xz
-z(4z - x)
sub back in for z
-(6x - 5y)[4(6x - 5y) - x]
-(6x - 5y)(24x - 20y - x)
-(6x - 5y)(23x - 20y)
(6x - 5y) is a factor, so
(6x - 5y)[x - 4(6x - 5y)]
(6x - 5y)[x - 24x + 20y]
(6x - 5y)(20y - 23x)
x(6x - 5y) - 4(6x - 5y)^2
let
z = 6x - 5y
xz - 4z^2
-4z^2 + xz
-z(4z - x)
sub back in for z
-(6x - 5y)[4(6x - 5y) - x]
-(6x - 5y)(24x - 20y - x)
-(6x - 5y)(23x - 20y)
singindre824:
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Answered by
99
Hi friend
--------------
Your answer
--------------------
★ FACTORISATION
------------------------------
x(6x - 5y) - 4(6x - 5y)²
=> (6x - 5y)[ x - 4(6x - 5y)]
=> (6x - 5y)(x - 24x + 20y)
=> (6x - 5y)(- 23x + 20y)
HOPE IT HELPS
--------------
Your answer
--------------------
★ FACTORISATION
------------------------------
x(6x - 5y) - 4(6x - 5y)²
=> (6x - 5y)[ x - 4(6x - 5y)]
=> (6x - 5y)(x - 24x + 20y)
=> (6x - 5y)(- 23x + 20y)
HOPE IT HELPS
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