X/7+y=-11/7 ...1
X-5y/3=2 ...2
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Answered by
1
see your first equation will be x+7y = -11 and second will be 3x-5y=6
and by multiplying 3 in eqn.1 nad subtracting from 2 y=-3/2 and then x =-1/2
and by multiplying 3 in eqn.1 nad subtracting from 2 y=-3/2 and then x =-1/2
ravyaarora2001:
Thanks so much❤️
no problem
thanks
Answered by
2
In equation 1
x/7+11/7=-y
=&x+11=-7y
=& x=-7y-11......3
In eq 2
x-5y/3=2
3x-5y=6
x=(6+5y)/3....4
Now from eq 3&4
-11-7y=(6+5y)/3
-33-21y=6+5y
26y=-39
y=-39/26
=-3/2
Substitute value of y in eq 4
x=(6+5×-3/2)/3. {Take -3/2 as -1.5)
=(6-7.5)/3
=-1.5/3
=-1/2
Thanks so much
Sorry I had to correct
Got confused that it was (x-5y)/3 instead of x-5y/3
Had to correct the process
And please if the answer has been helpful mark it as best ,I need to gain a rank
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