x/7+y/3=5;x/2-y/9=6
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x/7 + y/3 = 5 ………..(a)
x/2 - y/9 = 6 …………(b)
Now,
From (a) we have :-
(3x + 7y)/21 = 5
3x + 7y = 5 × 21
3x + 7y = 105 ………(c)
Now,
From (b) we have :-
(9x - 2y)/18 = 6
9x - 2y = 6 × 18
9x - 2y = 108 ………(d)
Now,
From (d) we have :-
3x = 105 - 7y
x = (105 - 7y)/3 ………..(4)
Putting this value of x in (d) :-
9x - 2y = 108
9(105 - 7y)/3 - 2y = 108
(945 - 63y)/3 - 2y = 108
945 - 63y - 6y = 108 × 3
945 - 63y - 6y = 324
-69y = 324 - 945
69y = 621
y = 621/69
y = 9
Now,
Substituting this value in (d) :-
x = (105 - 7 × 9)/3
x = (105 - 63)/3
x = 42/3
x = 14
Therefore,
x = 14 & y = 9
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