x^8-1, factorize
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Answer:
Given : x8 - 1
We can write this as :
=>(x4)² - (1)
Identity : a²-b² = (a - b)(a + b)
Here, a = x⁴, b=1
=>(x⁴ - 1)(x⁴ + 1)
We can write this as :
[(x²)² - (1)²](x⁴+ 1)
Identity : a²-b² = (a - b)(a + b)
Here, a = x², b = 1
=> (x² - 1)(x⁴+ 1)(x + 1)
We can write this as :
-:- [(x)² - (1)²] (x²+ 1)(x⁴+ 1)
Identity : a²-b² = (a - b)(a + b)
Here, a = x, b = 1
:- (x - 1)(x + 1)(x² + 1)(x⁴+ 1)
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