Question

X^8-y^8 With suitable identity

Answer 1

Answer:

Step-by-step explanation:

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Answer 2

Answer:

(x+y)(x-y)(x^2+y^2){(X^2)^2+(x^2)^2}

Step-by-step explanation:x^8 - y^8

= (X^4)^2 - (y^4)^2

=(x^4 + y^4)(x^4 - y^4)                 [by using identity{ A^2 - B^2 = (A - B)(A+B)}]

={(X^2)^2+(x^2)^2} {(x^2)^2-(y^2)^2}

={(X^2)^2+(x^2)^2}{(x^2+y^2)(x^2-y^2)}       [by using same identity]

={(X^2)^2+(x^2)^2}{(x^2+y^2)(x+y)(x-y)}

=(x+y)(x-y)(x^2+y^2){(x^2)^2(x^2+y^2)}