Question

X^9-x having ...... factor

Answer 1

$x( {x}^{8} - 1)$
$= x( { {(x}^{4} )}^{2} - 1)$
$= x( {x}^{4} + 1)( {x}^{4} - 1)$
$= x( {x}^{4} + 1)( { {(x}^{2}) }^{2} - 1)$
$= x( {x}^{4} + 1)( {x}^{2} + 1)( {x}^{2} - 1)$
$= x( {x}^{4} + 1)( {x}^{2} + 1)(x + 1)(x -1)$
Mark this answer as brainliest answer

Answer 2

$x ({x}^{8} - 1) \\ = x( {x}^{4} - 1)( {x}^{4} + 1) \\ = x( {x}^{4} + 1)( {x}^{2} + 1)( {x}^{2} - 1) \\ = x( {x}^{4} + 1)( {x}^{2} + 1)(x + 1)(x - 1)$
This is your answer.....