x=a(3costheta+cos3theta) find the second order derivative
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Answer :
(d²y / dx²) = (-6a cos Φ )
Step-by-step explanation:
x = a(3cosΦ+cos3Φ)
Differentiation wrt Φ
(dx / dΦ) = a x d/dΦ(3cosΦ+cos3Φ)
= a ( 3 (-sin Φ )+( -sinΦ) x (d/dx(3Φ))
= a (3 (- sinΦ ) + ( - sinΦ ) x (3))
= a (- 3sinΦ - 3sinΦ )
= a (-3) (sinΦ + sinΦ )
= -3a (2 sin Φ)
(dx /dΦ)= -6a (sinΦ)
again differentiate wrt Φ
(d²x / dΦ²) = d/dx( -6a (sinΦ ) )
=( -6a (d /dx (sinΦ))
= (-6a ( cos Φ))
= (-6a cosΦ )
(d²x / dΦ²) = (-6a cos Φ )
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