Question

x^(a+b) (a^2 - ab+b^2) ×x^(b+c) (b^2 - bc+c^2) ×x^(c+a) (c^2-ca+a^2) =1

Answer 1

Hello Mate!

x^[( a + b )( a^2 - ab + b^2 )] × x^[( b + c )( b^2 - bc + c^2 )] × x^[( c + a )( c^2 - ac + a^2 )] = 1

Now, we know that, ( a + b )( a^2 - ab + b^2 )
= a^3 + b^3

x^( a^3 + b^3 ) × x^( b^3 + c^3 ) × x^( c^3 + a^3 ) = 1

x^( a^3 + b^3 + b^3 + c^3 + c^3 + a^3 ) = 1

x^[ 2 ( a^3 + b^3 + c^3 ) ] is not equal to 1

Hope it helps☺!✌