{x^(a + b)}^( a -b){x^(b+c)}^(b-c){x^(c+a)}^(c-a) =??
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Hope it helps............
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let p={x^(a+b)}^(a-b)= x^(a^2-b^2)
q={x^(b+c)}^(b-c)=x^(b^2-c^2)
r={x^(c+a)}^(c-a)=x^(c^2-a^2)
now
p*q*r=x^(a^2-b^2)*x^(b^2-c^2)*x^(c^2-a^2)
=x^(a^2-b^2+b^2-c^2+c^2-a^2)
=x^0=1
hope this helps:p
q={x^(b+c)}^(b-c)=x^(b^2-c^2)
r={x^(c+a)}^(c-a)=x^(c^2-a^2)
now
p*q*r=x^(a^2-b^2)*x^(b^2-c^2)*x^(c^2-a^2)
=x^(a^2-b^2+b^2-c^2+c^2-a^2)
=x^0=1
hope this helps:p
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