Question

(x^a+b)^a-b × (x^b+c)^b-c × (x^c+a)^c-a​

Answer 1

Answer:

(x^a+b)^a-b×(x^b+c)^b-c×(x^c+a)^c-a

=x^(a+b)(a-b) x^(b+c)(b-c) x^(c+a)(c-a)

=x^(a+b)(a-b)+(b+c)(b-c)+(c+a)(c-a)

=x^(a^2-b^2+b^2-c^2+c^2-a^2)

=x^0

=1