X^a(b-c)/x^(a-c) ÷ (x^b/x^a)^c = 1
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= X a(b-c) divided (xb)c
xb (a-c) (xa)
= x ab-ac divided xbc
x ab-bc xac
= x ab-ac-(ab-bc) x ac-be
= x ab-ac-ab+bc+ac-be=x0
=1
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