( x + a)/( b + c) + ( x + b)/( c + a) + ( x + c)/( a + b) +3 = 0
then, find the value of 3x
Answers
Answered by
7
Write 3 as 1+1+1 and add each "1" with each of the three terms
Thus (x+a)/(b+c) becomes (x+a+b+c)/(b+c)
Then equation will be
(x+a+b+c)[1/(b+c)+1/(c+a)+1/(a+b)] = 0
Thus x+a+b+c = 0
or 3x = -3(a+b+c)
Thus (x+a)/(b+c) becomes (x+a+b+c)/(b+c)
Then equation will be
(x+a+b+c)[1/(b+c)+1/(c+a)+1/(a+b)] = 0
Thus x+a+b+c = 0
or 3x = -3(a+b+c)
Answered by
4
The answer is 0.
Attachments:
Similar questions