x+a is a factor of 2x^2+2ax+5ax+10,then find a
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Answered by
3
Answer:
Step-by-step explanation:
x+a=0
x=-a
P(x) = 2(-a)2+2a(-a)+5a(-a)+10=0
P(x) = 2a2-2a2-5a2+10=0
P(x) = - 5a2+10=0
P(x) = 5a2 = 10
a= root 5
Hope this helps
Answered by
0
x+a=0
x=-a
P(-a)=0
2*(-a)^2+7a*-a+10=0
2a^2-7a^2=-10
-5a^2=-10
5a^2=10
a^2=10/5
a^2=2
a= root 2
This is the correct answer
Hope the answer was useful
Thank you
x=-a
P(-a)=0
2*(-a)^2+7a*-a+10=0
2a^2-7a^2=-10
-5a^2=-10
5a^2=10
a^2=10/5
a^2=2
a= root 2
This is the correct answer
Hope the answer was useful
Thank you
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