Question

(x-a) (x-b)+(x-b) (x-c) + (x-c) (x-a) =0 will have equal roots if ,and only if, a=b=c.

Answer 1

hello mate

Sri here

$(x - a)(x - b) + (x - b) \\ (x - c) + (x - c)(x - a) = 0\\ {x}^{2} - xb - xa + ab + \\ {x}^{2} - xb- xc + bc+ \\ {x }^{2} - xa - xc + ac = 0\\ 3 {x}^{2} - 2xa - 2xb - 2xc + \\ ab + bc +ca = 0$
$i \: hope \: it \: is \: the \: answer$

I hope it is the answer