(x-a)(x-b)(x-c).........(x-z)?
Anonymous:
What do we have to find??
Answers
Answered by
3
Hey friend answer is 0 .
Because , (x-a)(x-b)........(x-x)(x-y)
(x-a)(x-b)........0×(x-y)
is 0 and when it will multiply with the term it will also become 0.
As 0 × any number is 0 only.
HOPE IT WILL HELP U.THANKSS................
Because , (x-a)(x-b)........(x-x)(x-y)
(x-a)(x-b)........0×(x-y)
is 0 and when it will multiply with the term it will also become 0.
As 0 × any number is 0 only.
HOPE IT WILL HELP U.THANKSS................
Answered by
11
HELLO DEAR,
(X-a)(x-b)(x-c).......(x-z)
=> (X-a)(x-b)(x-c).....(x-x)(x-y)(x-z)
=> (X-a)(x-b)(x-c)......×0(x-y)(x-z)
=> 0
I HOPE ITS HELP YOU DEAR,
THANKS
(X-a)(x-b)(x-c).......(x-z)
=> (X-a)(x-b)(x-c).....(x-x)(x-y)(x-z)
=> (X-a)(x-b)(x-c)......×0(x-y)(x-z)
=> 0
I HOPE ITS HELP YOU DEAR,
THANKS
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