Question

X/a+y/b=a+b; x/a^2+ y/b^2=2

Answer 1

\left[x \right] = \left[ \frac{ - \left( \left( -2\right) \,a^{2}\,b^{2}+a^{2}\,y\right) }{b^{2}}\right][x]=[​b​2​​​​−((−2)a​2​​b​2​​+a​2​​y)​​]



\left[X \right] = \left[ \frac{ - \left( - a^{2}\,b-a\,b^{2}+a\,y\right) }{b}\right][X]=[​b​​−(−a​2​​b−ab​2​​+ay)​​]


Algebra functional value