x=acostheta, y=bsintheta then find d^2y/dx^2=
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and
Given that
and
Now, Differentiate (1), w. r. t. θ, we get
Now, Differentiate (2) w. r. t. θ, we get
So,
On substituting the values from equation (3) and (4), we get
Now, Differentiate both sides w. r. t. x, we get
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Answer:
and
Given that
and
Now, Differentiate (1), w. r. t. θ, we get
Now, Differentiate (2) w. r. t. θ, we get
So,
On substituting the values from equation (3) and (4), we get
Now, Differentiate both sides w. r. t. x, we get
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