Question

x and y are angles on a triangle line forming linear pair. If twice of X is 30° less than Y , find x and y.

Answer 1

2x=30 degree
x=30/2
x=15 degree
x+y=180 degree (linear pair)
15 degree + y = 180 degree
y=180 degree -15 degree
y=65 degree
so,x =15 degree and y=65 degree
this may help you better!

Answer 2

Answer:

$\angle x =50^{\circ}$

$\angle y =1300^{\circ}$

Step-by-step explanation:

We are given that x and y are angles on a triangle line forming linear pair.

So, $x+y=180^{\circ}$   --1

We are also given that twice of X is 30° less than Y

$\Rightarrow  2x+30^{\circ} = y$  --2

Substitute the value of y from 1 in 2

$\Rightarrow 2x+30^{\circ} = 180^{\circ}-x$

$\Rightarrow 3x= 150$

$\Rightarrow x= \frac{150}[3}$

$\Rightarrow x= 50^{\circ}$

Substitute the value of x in 1

$50^{\circ}+y=180^{\circ}$

$y=180^{\circ}-50^{\circ}$

$y=130^{\circ}$

Thus $\angle x =50^{\circ}$

$\angle y =1300^{\circ}$