Question

X and Y measured their body temperature. X found its to be 98.6 °F and Y recorded 37 °C. Which of the following statement is true? (a) X has a higher body temperature than Y. (b) X has a lower body temperature than Y. (c) Both have normal body temperature. (d) Both are suffering from fever

Answer 1

Answer:

c

Explanation:

c is the correct answer

f=1.8c+32

1.8×37+32

66.6+32=98.6

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Answer 2

Answer:

The temperature of both X and Y in °C is 37°C.

Therefore, option c) Both have normal body temperature, is the correct answer.

Explanation:

Given,

The body temperature of X = 98.6°F

The body temperature of Y = 37°C

As we know,

• The normal temperature of a human body is 37°C.
• So, the body temperature of Y is normal body temperature.

Lets find out the body temperature of X into °C.

• Convert the °F in °C

The relation between the degree Celsius (°C) and the degree Fahrenheit (°F) is given below:

• $\textdegree C = [ \textdegree F - 32] \times \frac{5}{9}$

Now, after putting the value of °F in the equation, we get:

• $\textdegree C = [ 98.6 - 32] \times \frac{5}{9}$
• $\textdegree C = [ 66.6] \times \frac{5}{9}$
• $\textdegree C = 37 \textdegree C$

Therefore, the body temperature of Y in °C = 37°C

Hence, the temperature of both X and Y is 37°C, which is a normal human body temperature.