X and Y together can do a piece of work in 32 days. Y alone can do the same work in 48 days. How many days are required by X alone to complete 3/4th of the work?
Answers
Answered by
1
Answer:
Step-by-step explanation:
X+y = 32 and y=48 then find out total work by taking lcm of both .
Total work =96 nd efficiency of x=1 nd y =2 so 96/1*3/4=72
Similar questions