Question

X=asint and y= bcos2t find Derivative.

Answer 1

$\bold{x=a.sint}\\\\\bold{\frac{dx}{dt}=\frac{d}{dt}[a.sint] }\\\\\bold{\frac{dx}{dt}=a\frac{d}{dt}[sint]\;,(Here\;a\;is\;constant)}\\\\\bold{\frac{dx}{dt}=a.cost }$

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$\bold{y=b.cos2t}\\\\\bold{\frac{dy}{dt}=b.\frac{d}{dt}[cos2t] }\\\\\bold{\frac{dy}{dt}=b.(-2.sin2t)}\\\\\bold{\frac{dy}{dt}=-2b.sin2t}$

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More Information :

• Derivative of sin t  is cos t
• While derivating with respect to x or something remaining are considered as constants
• Derivative of cos t is - sin t