Math, asked by kanupriyaagarwal9068, 15 days ago

(x^b/x^c)^a * (x^c/x^a)^b * ( x^a/x^b) ^c​

Answers

Answered by qamarshakilsg618618
1

Answer:

(\frac{x^{b} }{x^{c} })^{a}×(\frac{x^{c} }{x^{a} })^{b}×(\frac{x^{a} }{x^{b} })^{c}

=( x^{b-c})^{a}×( x^{c-a})^{b}×( x^{a-b})^{c}

=( x^{b-c}*x^{c-a}*x^{a-b})^{a+b+c}

=(x^{b-c+c-a+a-b})^{a+b+c}

=now we know that b-c+c-a+a-b=0

=(x^{0})^{a+b+c

=any number raise to the power 0 is always equals to 1 so,

1^{a+b+c}

1 raise to any power is always equals to1

=(\frac{x^{b} }{x^{c} })^{a}×(\frac{x^{c} }{x^{a} })^{b}×(\frac{x^{a} }{x^{b} })^{c}=1

hope this helped you it took a a lot of time to solve in a computer

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