Question

X can do a piece of work in 20 days and y can do it in 10 days. they started together, but after 6 days x leaves off. y will do the rest work in

Answer 1

x can do a piece of work in 20 days.
one day work of x=1/20

Y can do a piece of work in 10 days.
One day work of y=1/10

(X+Y)'s one day work=
[
$= > \frac{1}{20} + \frac{1}{10} \\ = > \frac{1 + 2}{20} \\ = > \frac{3}{20}$

They worked for 6 day ,so the work done in these 6 days=
$= > \frac{3}{20} \times 6 \\ = > \frac{9}{10}$
So,
Remain work=
$= > 1 - \frac{9}{10} \\ = > \frac{10 - 9}{10} \\ = > \frac{1}{10}$
Therefore,the remain work done by Y in
$= > \frac{1}{10} \div \frac{1}{10 } \\ = > \frac{1}{10} \times \frac{1}{10} \\ = > 1$
Hence,the remine work done by Y in 1 days.