X can finish 2/3 of a work in 6 days and Y can finish 3/4 of the same work in 9 days. They worked together for 2 days and then Y left. The remaining work was done by X. How much time did X take to finish the remaining work?
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Answer:
x can finish 2/3 of work in 6 days
x can finish 1 whole work in 6÷2/3= 6×3/2 = 9 days
x can finish 1/9 of work in day
y can finish 3/4 of work in 9 days
y can finish 1 whole work in 9÷3/4 =9×4/3= 12 days
y can finish 1/12 part of work in 1 day
work done by X and y in 1 day
= 1/9 + 1/12 = 4+3/36 = 7/36
work done by x and y in 2 days = 2× 7/36 = 7/18
remaining work = 1 - 7/18 = 11/18
x does 1/9 part of work in 1 day
x does 11/18 part of work in 9×11/18 = 11/2 = 5 1/2 days
x does remaining part of work in 5 1/2 days
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Thank you very much for you kind words
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