x*cosec2 30*sec2 30/cos2 45*sin2 60=sin2 60/cos2 60-sin2 30/cos2 30.find the value of x
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substitute values using trigonometry table
X*2^2*(2/√3)^2/(3/√2)^2*(√3/2)^2=(√3/2)^2/(1/2)^2-(1/2)^2/(√3/2)^2
ON SIMPLYFYING WE GET
X*4*8/3*3/4=12/4-4/12
FURTHER
X*8=8/3
X=8/3*1/8
X=1/3
therefore x=1/3
X*2^2*(2/√3)^2/(3/√2)^2*(√3/2)^2=(√3/2)^2/(1/2)^2-(1/2)^2/(√3/2)^2
ON SIMPLYFYING WE GET
X*4*8/3*3/4=12/4-4/12
FURTHER
X*8=8/3
X=8/3*1/8
X=1/3
therefore x=1/3
Anonymous:
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