X=cota+cosa and y = cota-cosa ; prove that (x-y/x+y)^2 + (x-y/2)^2= 1
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x - y = 2cosA
x + y= 2cotA
[(x - y) / (x + y)]^2 =[ cosA / (cosA/sinA)]^2
= sin^2(A)
(x - y / 2 )^2 = 4cos^2(A) / 4
= cos^2(A)
adding them
sin^2(A) + cos^2(A) = 1
Hence proved
Hope it helps!!!
x + y= 2cotA
[(x - y) / (x + y)]^2 =[ cosA / (cosA/sinA)]^2
= sin^2(A)
(x - y / 2 )^2 = 4cos^2(A) / 4
= cos^2(A)
adding them
sin^2(A) + cos^2(A) = 1
Hence proved
Hope it helps!!!
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