X cube minus 3 x square - 9 x minus 5 divided by X + 1
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f(x)=x³-3x²-9x-5
g(x)=x+1=0
=x=-1
f(-1)=(-1)³-3(-1)²-9(-1)-5
=-1-3+9-5
=0
So, f(x) is completely divisible by g(x)
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