Question

x cube + y cube + Z cube minus 3 x y z

Answer 1

Uhh Uhh 8Howrah butterscotch to my lovely 3and hhuuuuyif

Answer 2

Answer:

x³+y³+z³-3xyz

=(x+y+z)(x²+y²+z²-xy-yz-zx)

Step-by-step explanation:

/* we know the algebraic identity:

$\boxed {a^{3}+b^{3}+c^{3}-3abc\\=(a+b+c)(a^{2}+b^{2}+c^{2}-ab-bc-ca)}$ */

We have ,

x³+y³+z³-3xyz

=(x+y+z)(x²+y²+z²-xy-yz-zx)

•••♪