Physics, asked by fadilahkhanA, 1 month ago

X divisions on main scale of vernier calliper coincide with y divisions on vernier scale. If each division on main scale is of 1 mm, then least count of instrument is
(1) ((x-y)/x) mm

(2) ((y-x)/y) mm

(3) (x – y) mm

(4) (1/(x-y)) mm

Answers

Answered by bhabanidas19
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Correct option is

C

10N1

Given, N Vernier Scale Divisions(VSD)=(N−1)Main Scale Divisions(MSD)

1 VSD=(NN−1)MSD

L.C= Least count =1MSD−1VSD

L.C=(1−NN−1)MSD

         =N1MSD=N0.1cm=10N1cm

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