x dy/dx = y+2xe^-y/x
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Answer:
x dy/dx = y+2xe^-y/xx dy/dx = y+2xe^-y/xxub can go ggixd going to ht
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Step-by-step explanation:
xdy/dx=y+2e^-y/x
or,
dy/dx=(y+2e^-y/x) /x
let y=vx
so, dy/dx=v+xdv/dx
Now,
v+xdv/dx={vx+2e^-(vx/x) }
xdv/dx={vx+2e^-v}-v
xdv/dx=vx+2e^-v-vx
dv/dx=(2e^-v) /x
dv/2e^-v=dx/x
e^vdv/2=dx/x
integrating both side
we get,
e^v=logx+logc
e^y/x=logx+logc
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