Question

x grams of
CaCl2
is treated to precipitate
all the calcium in form of
CaCO . 3
This
CaCO3
is converted to CaO and the final
mass of this CaO is 5.6 grams. Find x:

Answer 1

Answer:

HOLA MATE HERE IA YOUR ANSWER

CaC03 + heat = CaO + CO2

x 1.62

100 56

x=1.62 x 100/56 = 2.89 g

Cross multiply through the equation and solve for X grams of CaCO3 we get 2.89 grams of CaCO3

Original reaction CaCl2 + Na2CO3 = CaCO3 + 2 NaCl

x 2.89

111 100

x = 2.89 x 111/100=3.2 g

Cross multiply again and solve for X grams of CaCl2, we get 3.2 grams CaCl2

% CaCl2 in original mixture 3.2 grams CaCl2 over l0 gms mixture = .32 or 32%

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