Question

√x>(x-1) using inequalities find the range for x ?

Answer 1

Answer:

For real numbers x, , in the above inequation,

1 - x should be positive or zero

=> x = 1 or less than 1 …………..(1)

Now, if x is negative, 1 - x will be positive but in that case LHS will be negative & RHS will be positive. So LHS can not be greater than RHS.

=> x can not be negative…………..(2)

Now, if we take x=0, LHS won't be greater than RHS

=> x can not be zero. ………………(3)

Now taking all 3 conditions into considerations..

We conclude that x > 0 but less than 1.

ie, 0 < x < 1

Now, if we substitute different values for x , lying between 0 to 1 in the given inequation

We get the range..

0.6180399 <,= x <,= 1 ……..ANS

Step-by-step explanation:

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Answer 2

Answer:

0.6180399 ≤ x ≤ 1

Step-by-step explanation:

√x>(x-1)

so,

root cannot be taken for negative numbers

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