Question

X= H+Acos theta y= k+bsin thets.prove that[ x- h]

- [ y- k] square= 1

Answer 1

(X-h)^2-(y-k)^2=a^2

X=h+a cos theta

Y=k+a sin theta

(H+a cos theta-h)^2÷(k+a sin theta-k)^2=

(a cos thet a)^2+(a sin theta)^2=

a^2 cos^2theta+ a^2 sin^2 theta=

a^2(sin^2 theta+ cos^2theta)=

a^2

Sorry for some typing erros.Please mark it as brainliest

Answer 2

Answer:

Explanation:

With a short method