X] + h2so4 [y] a colourless gas with irritating smell. [y] + k2cr2o7 + h2so4 green solution. X and y are :
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Answered by
4
So I am not sure about the framing of the question but I would like to answer it in a general equations , first of all this test is given by sulphur dioxide gas , and form chromium sulphate
Answered by
14
Hey dear,
● Answer -
X => MSO3
Y => SO2
● Explanation -
X must be some metal sulphite MSO3.
MSO3 + H2SO4 --> MSO4 + H2O + SO2
Here, Y must be SO2 which is colourless gas with irritating smell.
SO2 gas reacts with acidic K2Cr2O7 to give green solution of cupric sulphate.
SO2 + K2Cr2O7 + H2SO4 --> K2SO4 + Cr2(SO4)3 + H2O
Hope this helps you.
● Answer -
X => MSO3
Y => SO2
● Explanation -
X must be some metal sulphite MSO3.
MSO3 + H2SO4 --> MSO4 + H2O + SO2
Here, Y must be SO2 which is colourless gas with irritating smell.
SO2 gas reacts with acidic K2Cr2O7 to give green solution of cupric sulphate.
SO2 + K2Cr2O7 + H2SO4 --> K2SO4 + Cr2(SO4)3 + H2O
Hope this helps you.
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