X is now 9 year older than Y in next 10 years X will be twice as old as Y was 10 years ago what are the present age of X and Y
Abhishekpal111:
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2
present age of B = x and present age of A = (x+9)
After 10 years, age of A = x+9+10 = x +19
Before 10 years, age of B = (x-10)
Given that (x+19) = 2(x-10)
x + 19 = 2x - 20
x = 39
present age of B = 39
After 10 years, age of A = x+9+10 = x +19
Before 10 years, age of B = (x-10)
Given that (x+19) = 2(x-10)
x + 19 = 2x - 20
x = 39
present age of B = 39
Answered by
2
given: x=y+9
after 10 yrs. age of x=x+10=y+9+10
given, age of x=2(y-10)
=> y+19=2y-20
=> 39=2y-y
=> age of y=39 and age of x=39+9=48
after 10 yrs. age of x=x+10=y+9+10
given, age of x=2(y-10)
=> y+19=2y-20
=> 39=2y-y
=> age of y=39 and age of x=39+9=48
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