Question

x' is twice as old as 'y' 3 years ago, when 8. 'x' was as old as 'y' today. If the difference between their ages at present is 3 years, how old is 'x' at present

Answer 1

Answer:

Step-by-step explanation:

A is 6 years old now.

Let’s assume B’s age is x 2 years ago.

Then A’s age is 2x.

Now A-B =2.

Thus we have an equation:

x+2 = 2x

2x-x =2

Therefore, x= 2.

So B was 2 years old 2 years back. A was 4 Years then.

Thus, now A is 6 year sold.