Question

X कोनाचा पुरककोन त्याच्या पाचपट असल्यास x कोनाचा कोटिकोन किती मापाचा असेल?

Answer 1

SOLUTION

GIVEN

The complement of the x angle is five times of that angle

TO DETERMINE

The angle x

EVALUATION

Here the given angle = x

Then complement of the angle x

= 90° - x

Now by the given condition

90° - x = 5x

⇒ - x - 5x = - 90°

⇒ - 6x = - 90°

⇒ 6x = 90°

⇒ x = 15°

FINAL ANSWER

The angle x = 15°

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