Question

x^+kx+k has repeated roots. Find the value of k.​

Answer 1

hey

it must be square.

so ,

a+b=-b/a

=-k

ab=C/a =k

therefore..

k can be any square root vue that is

4

x2+4x+4

ans

Answer 2

${x}^{2} + kx + k$

has repeated roots i.e. both the roots are same

delta=0

${k}^{2} - 4k = 0 \\ \\ k(k - 4) = 0 \\ \\ k = 0 \\ \\ k = 4 \\ \\ if \: k = 0 \\ \\ x = 0 \: is \: the \: root\\ \\ if \: k = 4 \\ \\ x = - 2 \: is \: the \: root$

hope it helps.