Question

x-ky=2,3x+2y+5=0 find the value of k in which the system of equation has a unique solution

Answer 1

ASSALAMAALEKUM



here is ur solution .

hope u will understand.

Answer 2

$k\neq \dfrac{-2}{3}$

Step-by-step explanation:

Given,

The system of equation are

x - ky = 2

3x + 2y = - 5

To find, the value of k = ?

Here, $a_{1} =1,b_{1} =-k,c_{1} =2$ and

$a_{2} =3,b_{2} =2,c_{2} =-5$

The  condition of the the system of equation has a unique solution

$\dfrac{a_{1}}{a_{2}} \neq \dfrac{b_{1}}{b_{2}}$

∴ $\dfrac{1}{3} \neq \dfrac{-k}{2}$

⇒ $k\neq \dfrac{-2}{3}$

Hence, $k\neq \dfrac{-2}{3}$