x= log35 , y=log37 then express log335 in terms of ‘x’ and’y
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Answer:
sin3A=cos(A−10
o
)⇒cos(90
o
−3A)=cos(A−10
o
)
⇒90
o
+10
o
=3A+A⇒100
o
=4A⇒A=25
o
Therefore, Answer is 25
osin3A=cos(A−10
o
)⇒cos(90
o
−3A)=cos(A−10
o
)
⇒90
o
+10
o
=3A+A⇒100
o
=4A⇒A=25
o
Therefore, Answer is 25
osin3A=cos(A−10
o
)⇒cos(90
o
−3A)=cos(A−10
o
)
⇒90
o
+10
o
=3A+A⇒100
o
=4A⇒A=25
o
Therefore, Answer is 25
osin3A=cos(A−10
o
)⇒cos(90
o
−3A)=cos(A−10
o
)
⇒90
o
+10
o
=3A+A⇒100
o
=4A⇒A=25
o
Therefore, Answer is 25
o
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