x^logx=100x find the value of x
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Take loglog from both sides:
log(xlogx)=log(100x)
log(xlogx)=log(100x)
log(x)log(x)=log(100x)=log(100)+log(x)
log(x)log(x)=log(100x)=log(100)+log(x)
Or:
(logx)2−(logx)=2
(logx)2−(logx)=2
Now you have a quadratic equation which you should be able to solve.
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