Math, asked by harikr417, 10 months ago

(x^m/x^n)^l*(x^n/x^l)^m*(x^l/x^m)^n​

Answers

Answered by SonyLahari
1

Step-by-step explanation:

x^ml/x^mn*x^mn/x^ml*x^nl/x^mn

here ,x^ml/x^mn *x^mn/x^ml gets cancelled

then the resultant is = x^nl/x^mn is the answer

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