x minus 1 upon x minus b + x minus b upon x minus equals to upon B + b Upon A
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Answered by
109
Given:
Explanation:
Let m = (x-a)/(x-b) ----(1)
Now , equation becomes,
m+1/m = a/b+b/a
=>m-a/b = b/a - 1/m
=> (mb-a)/b = (bm-a)/am
Do the cross multiplication, we get
=> am(mb-a) = b(bm-a)
=> abm²-a²m=b²m-ab
=> abm²-a²m-b²m+ab=0
=> am(bm-a)-b(bm-a)=0
=> (bm-a)(am-b)=0
=> bm-a = 0 Or am-b=0
=> m = a/b or m = b/a
(x-a)/(x-b)=a/b Or (x-a)(x-b)=b/a
=> b(x-a)=a(x-b) Or a(x-a)=b(x-b)
=> bx-ab=ax-ab or ax-a²=bx-b²
=> bx-ax=0 or ax-bx = a²-b²
=> x(b-a)=0 or x(a-b)=(a+b)(a-b)
=> x = 0 Or x = [(a+b)(a-b)]/(a-b)
=> x = 0 Or x = a+b
Therefore,
x = 0 or x = a+b
••..
Answered by
25
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