Question

x minus 2 by 3 y whole cube minus x + 2 by 3 y whole cube​

Answer 1

Answer:

$\boxed{12x^3 - \dfrac{48x}{9y^2}}$

Step-by-step explanation:

$\left( x - \dfrac{2}{3y} \right)^3 - \left( x + \dfrac{2}{3y} \right)^3\\\\\\(a-b)^3 - (a+b)^3 = 6ab(a+b)\\\\\\\text{For its derivation, refer attachment.}\\\\\\\text{So, we have}\\\\\\6 \times \left( x - \dfrac{2}{3y} \right) \left( x + \dfrac{2}{3y} \right) \times \left[ \left( x - \dfrac{2}{3y} \right) + \left( x + \dfrac{2}{3y} \right) \right]\\\\\\\text{Also, (a+b)(a-b) = a^2 - b^2 }\\\\\\\text{So we have,}$

$6 \times \left[ (x)^2 - \left( \dfrac{2}{3y} \right)^2 \right] \times 2x\\\\\\\\= 12x \times \left( x^2 - \dfrac{4}{9y^2} \right)\\\\\\\\= \boxed{12x^3 - \dfrac{48x}{9y^2}}$

Answer 2

Step-by-step explanation:

ब्रैकेट वन बाय टू ए माइनस टू बाय 3 बाय होल क्यूब