Question

'X' moles of sodium borohydride (SBH) reduces 'y' moles acetaldehyde to ethyl alcohol. The value of 'x + y/20' is​

Answer 1

Answer:

0.25

Explanation:

1 mole of NaBH4 reacts with 4 miles of acetaldehyde to form 1mole ethyl alcohol

therefore, 1+4/20=0.25

Answer 2

Given:

X' moles of sodium borohydride (SBH) reduce 'y' moles acetaldehyde to ethyl alcohol.

To find:

The value of 'x + y/20'.

Solution:

Sodium borohydride reduces aldehyde or ketone to alcohol in the presence of an alcoholic solvent.

One mole of sodium boron hydride can react with four moles of acetaldehyde to form four moles of ethyl alcohol.

Thus, the value of X is 1.

The value of y is 4.

Thus we can write-

$1 + \frac{4}{20} \\ = 1 + 0.2 \\ = 1.2$

Hence the value of x+y/20 is 1.2.