Question

In the reaction N2H4 + 302 → 2NO2 + 2H20, the mass
of O2 required to combine with 745 g of N H4 will be​

Answer 1

Explanation:

no. of mole of N2H4 = 745/32

required moles of O2 = 745/32*3

mass of O2 = 745/32*3*32 = 2235