Question

[(x^n)^n-1/n]^1/n+1] is equal to​

Answer 1

Step-by-step explanation:

[(x^n)^n / (x^n)^1/n ]^1/n+1

= [ (x^n²) / (x) ]^1/n+1

=(x^(n²-1))^1/n+1

[ x^(n-1)(n+1)/(n+1) ]

= x^(n-1)